Question:

The carbon bond length in benzene is:

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Due to resonance, all C–C bonds in benzene are identical and have bond order 1.5, giving a bond length intermediate between single and double bonds.
Updated On: Jan 14, 2026
  • in between C\(_2\)H\(_6\) and C\(_2\)H\(_4\)
  • same as in C\(_2\)H\(_4\)
  • in between C\(_2\)H\(_6\) and C\(_2\)H\(_2\)
  • in between C\(_2\)H\(_4\) and C\(_2\)H\(_2\)
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The Correct Option is A

Solution and Explanation

Step 1: Recall carbon–carbon bond lengths in different hydrocarbons.

C–C single bond (as in C\(_2\)H\(_6\)) \(\approx 1.54\ \text{\AA}\)
C=C double bond (as in C\(_2\)H\(_4\)) \(\approx 1.34\ \text{\AA}\)
C\(\equiv\)C triple bond (as in C\(_2\)H\(_2\)) \(\approx 1.20\ \text{\AA}\)
Step 2: Nature of bonding in benzene. In benzene, all six carbon–carbon bonds are equivalent due to resonance. Each C–C bond has partial double bond character (bond order \(= 1.5\)). Step 3: Bond length in benzene. The C–C bond length in benzene is approximately: \[ 1.39\ \text{\AA} \] This value lies between the bond lengths of:

C–C single bond (C\(_2\)H\(_6\))
C=C double bond (C\(_2\)H\(_4\))
Step 4: Final conclusion. Hence, the carbon bond length in benzene lies in between C\(_2\)H\(_6\) and C\(_2\)H\(_4\).
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