Question:

What should be the amount of current through the ring of radius $5\, cm$ so that field in the centre is with earth?s magnetic field of $7 \times 10^{-9} \,Wb/m^2$ is

Updated On: Jul 5, 2022
  • 0.5 A
  • 0.28 A
  • 2.8 A
  • none
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The Correct Option is D

Solution and Explanation

Given that the field at the centre of the ring B = 7 ? 10 Wb/m We know that $B=\frac{\mu_{0}I}{2r}$ $\Rightarrow I=\frac{2Br}{\mu_{0}}$ $=\frac{2\times7\times 10^{-9}\times 0.05}{4\pi\times 10^{-7}}$ $=5.57\times 10^{-4}$ A
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Concepts Used:

Moving Charges and Magnetism

Moving charges generate an electric field and the rate of flow of charge is known as current. This is the basic concept in Electrostatics. Another important concept related to moving electric charges is the magnetic effect of current. Magnetism is caused by the current.

Magnetism:

  • The relationship between a Moving Charge and Magnetism is that Magnetism is produced by the movement of charges.
  • And Magnetism is a property that is displayed by Magnets and produced by moving charges, which results in objects being attracted or pushed away.

Magnetic Field:

Region in space around a magnet where the Magnet has its Magnetic effect is called the Magnetic field of the Magnet. Let us suppose that there is a point charge q (moving with a velocity v and, located at r at a given time t) in presence of both the electric field E (r) and the magnetic field B (r). The force on an electric charge q due to both of them can be written as,

F = q [ E (r) + v × B (r)] ≡ EElectric +Fmagnetic 

This force was based on the extensive experiments of Ampere and others. It is called the Lorentz force.