\(S.I = \frac{P\times R\times T}{100}\)
\(280=\frac{56000\times R\times 2}{100}\)
\(R= \frac{280}{560\times2}=\frac{1}{4}\)
= \(0.25\)
Therefore, \(0.25\%\) gives Rs \(280\) as interest on the given sum.
Read more: Simple Interest


Give first the step you will use to separate the variable and then solve the equation:
(a) x – 1 = 0
(b) x + 1 = 0
(c) x – 1 = 5
(d) x + 6 = 2
(e) y – 4 = – 7
(f) y – 4 = 4
(g) y + 4 = 4
(h) y + 4 = – 4