(a) Principal (P) = Rs \(1200\)
Rate (R) = \(12 \%\) p.a.
Time (T) = \(3\) years
\(S.I = \frac{P\times R\times T}{100}\)
= \(\frac{1200\times 12\times3}{100}\)
= Rs \(432\)
Amount = \(P + S.I\).
= \(1200 + 432\)
= Rs \(1632\)
(b) P = Rs \(7500\), R = \(5\%\) p.a.
T = \(3\) years
\(S.I = \frac{P\times R\times T}{100}\)
\(=\frac{7500\times5\times3}{100}\)
= Rs \(1125\)
Amount = \(7500 + 1125\)
= Rs \(8625\)
Read more: Simple Interest Formula
Write equations for the following statements:
(i) The sum of numbers x and 4 is 9.
(ii) 2 subtracted from y is 8.
(iii) Ten times a is 70.
(iv) The number b divided by 5 gives 6.
(v) Three-fourth of t is 15.
(vi) Seven times m plus 7 gets you 77.
(vii) One-fourth of a number x minus 4 gives 4.
(viii) If you take away 6 from 6 times y, you get 60.
(ix) If you add 3 to one-third of z, you get 30