Question:

What particles are emitted when \(^{206}_{82}Pb\) undergoes radioactive decay?

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Alpha decay involves the emission of a particle consisting of two protons and two neutrons, which reduces the atomic number and mass number by 2 and 4, respectively.
Updated On: Jan 12, 2026
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Solution and Explanation

When the isotope \(^{206}_{82}Pb\) undergoes radioactive decay, it typically emits an alpha particle. This means that it loses two protons and two neutrons, and the result is a new isotope with a lower atomic number by 2 and mass number by 4. This process is characteristic of the decay of heavy elements like lead. Thus, \( \alpha \) particles are emitted during the decay of \(^{206}_{82}Pb\).
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