The satellite is moving on around the earth, displacement of the object is perpendicular to the direction of force. \(θ = 90°\).
\(W = F×s \ cos\ θ\)
\(W= F×s\ cos\ 90°\)
\(W= F×0\)
\(W= 0\)
Therefore, work done is zero.
(i) The kind of person the doctor is (money, possessions)
(ii) The kind of person he wants to be (appearance, ambition)
ABCD is a quadrilateral in which AD = BC and ∠ DAB = ∠ CBA (see Fig. 7.17). Prove that
(i) ∆ ABD ≅ ∆ BAC
(ii) BD = AC
(iii) ∠ ABD = ∠ BAC.

Work is the product of the component of the force in the direction of the displacement and the magnitude of this displacement.
W = Force × Distance
Where,
Work (W) is equal to the force (f) time the distance.
W = F d Cos θ
Where,
W = Amount of work, F = Vector of force, D = Magnitude of displacement, and θ = Angle between the vector of force and vector of displacement.
The SI unit for the work is the joule (J), and it is defined as the work done by a force of 1 Newton in moving an object for a distance of one unit meter in the direction of the force.
Work formula is used to measure the amount of work done, force, or displacement in any maths or real-life problem. It is written as in Newton meter or Nm.