The given unbalanced chemical equation is: \[ YH_2 + O_2 \rightarrow XH_2O \] To balance this equation, let's first balance the hydrogen atoms. The left side has 1 hydrogen atom from \( YH_2 \), and the right side has 2 hydrogen atoms in \( H_2O \). Therefore, we need 2 \( YH_2 \) molecules on the left side to balance the hydrogen atoms: \[ 2YH_2 + O_2 \rightarrow XH_2O \] Next, balance the oxygen atoms. On the left side, we have 2 oxygen atoms in \( O_2 \), so we need 2 \( H_2O \) molecules on the right side to balance the oxygen atoms: \[ 2YH_2 + O_2 \rightarrow 2H_2O \]
The correct option is (C): \(2\)
\(\text{Reaction of aniline with conc. HNO}_3 \text{ and conc. H}_2\text{SO}_4 \text{ at 298 K will produce 47\% of:}\)