Question:

What is the value of \( \log_{10} 50 + \frac{\log_{0.5} 5}{1+\log_{2} 5} \)?

Show Hint

When faced with logarithms of multiple bases, the change of base rule is your best friend. Convert all terms to a single, convenient base (like 10 or e, or a base already present in the problem) to simplify the expression.
Updated On: Feb 14, 2026
  • 0
  • 1
  • 3
  • 2
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is B

Solution and Explanation

Step 1: Understanding the Question:
We need to evaluate a numerical expression involving logarithms with different bases.
Step 2: Key Formula or Approach:
We will use the properties of logarithms to simplify the expression. The key properties are: 1. Change of Base Formula: \(\log_a b = \frac{\log_c b}{\log_c a}\) 2. Logarithm of a power: \(\log_a (b^n) = n \log_a b\) 3. Logarithm of a product: \(\log_a (bc) = \log_a b + \log_a c\) 4. Logarithm of a quotient: \(\log_a (\frac{b}{c}) = \log_a b - \log_a c\)
It is often helpful to convert all logarithms to a common base. Let's use base 10 or base 2.
Step 3: Detailed Explanation:
Let's simplify the second term of the expression first: \( \frac{\log_{0.5} 5}{1+\log_{2} 5} \).
First, simplify the numerator, \(\log_{0.5} 5\). \[ \log_{0.5} 5 = \log_{1/2} 5 \] Using the change of base formula to base 2: \[ \log_{1/2} 5 = \frac{\log_2 5}{\log_2 (1/2)} = \frac{\log_2 5}{\log_2 (2^{-1})} = \frac{\log_2 5}{-1} = -\log_2 5 \] Now substitute this back into the fraction: \[ \frac{\log_{0.5} 5}{1+\log_{2} 5} = \frac{-\log_2 5}{1+\log_{2} 5} \] This does not seem to simplify well. Let's try changing all bases to a common base 'c'. \[ \frac{\frac{\log_c 5}{\log_c 0.5}}{1 + \frac{\log_c 5}{\log_c 2}} = \frac{\frac{\log_c 5}{\log_c (1/2)}}{ \frac{\log_c 2 + \log_c 5}{\log_c 2}} = \frac{\frac{\log_c 5}{-\log_c 2}}{ \frac{\log_c (2 \times 5)}{\log_c 2}} = \frac{-\log_c 5 / \log_c 2}{\log_c 10 / \log_c 2} = \frac{-\log_c 5}{\log_c 10} \] Using the change of base formula again, this is equal to \(-\log_{10} 5\).
So the original expression becomes: \[ \log_{10} 50 + (-\log_{10} 5) \] \[ = \log_{10} 50 - \log_{10} 5 \] Using the quotient rule for logarithms: \[ = \log_{10} \left(\frac{50}{5}\right) \] \[ = \log_{10} 10 \] \[ = 1 \] Step 4: Final Answer:
The value of the expression is 1.
Was this answer helpful?
0
0

Questions Asked in SRCC GBO exam

View More Questions