Question:
What is the third term in a sequence of numbers that leave remainders of 1, 2 and 3 when divided by 2, 3 and 4 respectively?
What is the third term in a sequence of numbers that leave remainders of 1, 2 and 3 when divided by 2, 3 and 4 respectively?
Updated On: Oct 3, 2024
- 11
- 17
- 19
- 35
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The Correct Option is D
Solution and Explanation
L.C.M. (2,3,4) = 12
Number of the form that leave remainders of 1, 2 and 3 when divided by 2, 3 and 4 respectively =\(12x−1\)
Therefore,\((2−1)=(3−2)=(4−3)=1\), where \(x\) is a natural number
Thus, the third number =\(12(3)−1=35\)
The correct answer is (D): 35
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