To find the probability that a five-digit number has at least one zero in it, we can use the complementary probability approach. Let's go through the solution step-by-step:
First, calculate the total number of five-digit numbers. A five-digit number ranges from 10000 to 99999. Therefore, the total number of five-digit numbers is 99999 - 10000 + 1 = 90000.
Next, determine the number of five-digit numbers that do not contain any zeros. For a number to have no zeros:
Therefore, the total number of five-digit numbers with no zeros is 9^5. Calculating this gives:
9^5 = 9 \times 9 \times 9 \times 9 \times 9 = 59049Now, use the complementary probability to find the number of five-digit numbers with at least one zero:
90000 - 59049 = 30951
Finally, calculate the probability that a five-digit number has at least one zero:
Probability = \frac{30951}{90000}
Simplifying the fraction gives approximately 0.344.
Therefore, the probability that a five-digit number has at least one zero in it is 0.344.
Four students of class XII are given a problem to solve independently. Their respective chances of solving the problem are: \[ \frac{1}{2},\quad \frac{1}{3},\quad \frac{2}{3},\quad \frac{1}{5} \] Find the probability that at most one of them will solve the problem.