What is the pH of the solution containing 1.342 x 10–3 M H+ ions? (log 1.342 =0.1277)
Given that the concentration of H+ ions is 1.342 x 10-3 M
we can use the logarithmic relationship to determine the pH:
pH = -log[H+]
Using the given value for log 1.342 (which is 0.1277), we can substitute it into the equation:
pH = -log(1.342 x 10-3)
pH = -(log 1.342 + log 10-3)
pH = -(0.1277 + (-3))
pH = -(0.1277 - 3)
pH = -(-2.8723)
pH = 2.8723
Rounding the pH value to two decimal places, the pH of the solution is approximately 2.87.
Therefore, the correct answer is option (C) 2.87.
Consider the following equilibrium,
CO(g) + 2H2(g) ↔ CH3OH(g)
0.1 mol of CO along with a catalyst is present in a 2 dm3 flask maintained at 500 K. Hydrogen is introduced into the flask until the pressure is 5 bar and 0.04 mol of CH3OH is formed. The Kp is ____ × 10-3 (nearest integer).
Given: R = 0.08 dm3 bar K-1mol-1
Assume only methanol is formed as the product and the system follows ideal gas behaviour.
The pH of a 0.01 M weak acid $\mathrm{HX}\left(\mathrm{K}_{\mathrm{a}}=4 \times 10^{-10}\right)$ is found to be 5 . Now the acid solution is diluted with excess of water so that the pH of the solution changes to 6 . The new concentration of the diluted weak acid is given as $\mathrm{x} \times 10^{-4} \mathrm{M}$. The value of x is _______ (nearest integer).
A body of mass $m$ is suspended by two strings making angles $\theta_{1}$ and $\theta_{2}$ with the horizontal ceiling with tensions $\mathrm{T}_{1}$ and $\mathrm{T}_{2}$ simultaneously. $\mathrm{T}_{1}$ and $\mathrm{T}_{2}$ are related by $\mathrm{T}_{1}=\sqrt{3} \mathrm{~T}_{2}$. the angles $\theta_{1}$ and $\theta_{2}$ are