Question

What is the oxidation state of sulfur in H\(_2\)SO\(_4\)?

• A. +4
• B. +6
• C. +7
• D. +2

Hint:

To determine the oxidation state of an element in a compound, balance the charges of the atoms in the molecule, knowing the oxidation states of the other atoms.

Answer 1

The Correct Option is B

In \( H_2SO_4 \), hydrogen has an oxidation state of +1, and oxygen has an oxidation state of -2. The total charge on the molecule is 0, so the sum of the oxidation states of all atoms in \( H_2SO_4 \) must also be 0. Let the oxidation state of sulfur be \( x \). The equation for the oxidation states is: \[ 2(+1) + x + 4(-2) = 0 \] Simplifying: \[ 2 + x - 8 = 0 \] \[ x - 6 = 0 \] \[ x = +6 \] Therefore, the oxidation state of sulfur in \( H_2SO_4 \) is +6.