Question:
What is the molarity of a solution prepared by dissolving 5.85 g of NaCl in 500 mL of water?
(Molar mass of NaCl = 58.5 g/mol)
What is the molarity of a solution prepared by dissolving 5.85 g of NaCl in 500 mL of water?
(Molar mass of NaCl = 58.5 g/mol)
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Molarity = moles of solute / volume of solution in liters.
Updated On: Jun 13, 2025
- 0.1 M
- 0.2 M
- 1.0 M
- 2.0 M
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The Correct Option is B
Solution and Explanation
- Calculate the number of moles of NaCl: \[ \text{moles} = \frac{5.85\, \text{g}}{58.5\, \text{g/mol}} = 0.1\, \text{mol} \] - Volume of solution = 500 mL = 0.5 L - Molarity (M) = \(\frac{\text{moles}}{\text{volume in liters}} = \frac{0.1}{0.5} = 0.2\, \text{M}\)
Answer: \(\boxed{\text{B}}\)
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