Question

What is the magnetic moment of a divalent ion with three unpaired electrons?

• A. 2.84 BM
• B. 5.92 BM
• C. 3.87 BM
• D. 4.90 BM
• E. 1.73 BM

Hint:

The magnetic moment can be calculated for transition metal ions using the formula \( \mu = \sqrt{n(n+2)} \), where \( n \) is the number of unpaired electrons.

Answer 1

The Correct Option is C

The magnetic moment of a transition metal ion can be calculated using the formula:
\[ \mu = \sqrt{n(n+2)} \, \text{BM} \] Where: - \( n \) is the number of unpaired electrons. Given that the ion has 3 unpaired electrons, we substitute \( n = 3 \) into the formula: \[ \mu = \sqrt{3(3+2)} = \sqrt{3 \times 5} = \sqrt{15} \approx 3.87 \, \text{BM} \] Thus, the magnetic moment of the divalent ion with three unpaired electrons is 3.87 BM. Therefore, the correct answer is (C) 3.87 BM.