Number of hybrid orbitals $(X)$ $=\frac{1}{2}(V.E. +M.A. -c+a)$ For, $XeOF_{4}$ $V.E. =8; M.A.$ (monovalent atoms) $= 4$ $(X)=\frac{1}{2}(8+4)\Rightarrow 6$ i.e., $sp^{3} d^{2}$ hybridisation
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The compound XeOF4, has 5 sigma bonds, 1 pi bond and 1 lone pair. The sum of sigma and lone pair is 5 + 1= 6. It means that there is one s orbital, 3 p orbitals and 2 d orbitals.
Therefore, the hybridization is sp3 d2.
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Top Questions on Chemical bonding and molecular structure
Such a group of atoms is called a molecule. Obviously, there must be some force that holds these constituent atoms together in the molecules. The attractive force which holds various constituents (atoms, ions, etc.) together in different chemical species is called a chemical bond.
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