Question:
What is the focal length of a plano-convex lens if 'R' is the radius of curvature and ‘n’ is the refractive index?
What is the focal length of a plano-convex lens if 'R' is the radius of curvature and ‘n’ is the refractive index?
Updated On: Jun 1, 2024
- \(f=R\)
- \(f=\frac R2\)
- \(f=\frac {R}{n-1}\)
- \(f=\frac {n-1}{R}\)
Hide Solution
Verified By Collegedunia
The Correct Option is C
Solution and Explanation
The correct option is (C): \(f=\frac {R}{n-1}\).
Was this answer helpful?
0
0
Top Questions on Reflection Of Light By Spherical Mirrors
- A spherical ball of mass \( 20 \) kg is stationary at the top of a hill of height \( 100 \) m. It rolls down a smooth surface to the ground, then climbs up another hill of height \( 30 \) m and finally rolls down to a horizontal base at a height of \( 20 \) m above the ground. The velocity attained by the ball is:
- BITSAT - 2024
- Physics
- Reflection Of Light By Spherical Mirrors
- A simple pendulum doing small oscillations at a place \( R \) height above the Earth's surface has a time period of \( T_1 = 4 \, {s} \). \( T_2 \) would be its time period if it is brought to a point which is at a height \( 2R \) from the Earth's surface. Choose the correct relation [\( R \) = radius of Earth]:
- BITSAT - 2024
- Physics
- Reflection Of Light By Spherical Mirrors
- A light ray is incident on the surface of a sphere of refractive index n at an angle of incidence \(\theta_0\). The ray partially refracts into the sphere with angle of refraction \(\phi\) and then partly reflects from the back surface. The reflected ray then emerges out of the sphere after a partial refraction. The total angle of deviation of the emergent ray with respect to the incident ray is \(a\). Match the quantities mentioned in List-I with their values in List-II and choose the correct option.
List-I List-II P If \(n = 2\) and \(\alpha = 180°\), then all the possible values of \(\theta_0\) will be I \(30\degree\) or \(0\degree\) Q If \(n = √3\) and \(\alpha= 180°\), then all the possible values of \(\theta_0\) will be II \(60\degree\) or \(0\degree\) R If \(n = √3\) and \(\alpha= 180°\), then all the possible values of \(\phi_0\) will be III \(45\degree\) or \( 0\degree\) S If \(n = \sqrt2\) and \(\theta_0 = 45°\), then all the possible values of \(\alpha\) will be IV \(150\degree\) \[0\degree\] - JEE Advanced - 2024
- Physics
- Reflection Of Light By Spherical Mirrors
- An object is placed 15 𝑐𝑚 in front of a convex mirror, which has a radius of curvature 30 𝑐𝑚. Which one of the following is true of the image formed?
- IIT JAM BT - 2024
- Physics
- Reflection Of Light By Spherical Mirrors
- Light from a point source in air falls on a convex curved surface of radius 20 cm and refractive index 1.5. If the source is located at 100 cm from the convex surface, the image will be formed at____ cm from the object.
- JEE Main - 2024
- Physics
- Reflection Of Light By Spherical Mirrors
View More Questions
Questions Asked in TS POLYCET exam
- The value of \(\tan 26^\circ. \tan 64^\circ\) is
- TS POLYCET - 2023
- Trigonometry
- In the figure, if AP and AQ are the two tangents to a circle with centre 'O' so that \(∠OQP=15°\), then \(∠QAP=\)
- TS POLYCET - 2023
- Tangent to a Circle
- If 5x+py+8=0 and 10x+15y+12=0 has no solution, then p =
- TS POLYCET - 2023
- Quadratic Equations
- When white light is incident on a glass prism, the least deviated colour is
- TS POLYCET - 2023
- Wave Optics
- If \(\sec \theta = \frac{2}{\sqrt{3}}\),then \(cosθ=\)
- TS POLYCET - 2023
- Trigonometry
View More Questions