Step 1: Recall the definition of empirical formula
The empirical formula of a compound represents the simplest whole-number ratio of the elements present in the compound.
Step 2: Simplify the molecular formula
The molecular formula of the compound is \( \text{C}_6\text{H}_6 \), which shows 6 carbon atoms and 6 hydrogen atoms.
To obtain the empirical formula, divide both the number of carbon atoms and the number of hydrogen atoms by the greatest common divisor (GCD) of 6. \[ \frac{6}{6} : \frac{6}{6} = 1 : 1 \] Thus, the empirical formula is \( \text{CH} \).
Answer:
Therefore, the empirical formula of \( \text{C}_6\text{H}_6 \) is \( \text{CH} \). So, the correct answer is option (1).
List-I | List-II | ||
(A) | 1 mol of H2O to O2 | (I) | 3F |
(B) | 1 mol of MnO-4 to Mn2+ | (II) | 2F |
(C) | 1.5 mol of Ca from molten CaCl2 | (III) | 1F |
(D) | 1 mol of FeO to Fe2O3 | (IV) | 5F |