Question:

What is the difference between the average runs of top two openers in terms of \emph{highest runs, if matches having 0's were ignored?}

Show Hint

When an average is asked "ignoring 0's", divide total runs by the number of innings \emph{with positive scores} (\(= \text{matches} - \text{ducks}\)), not by 20.
Updated On: Aug 20, 2025
  • 11.1
  • 13.7
  • 4.7
  • None of these
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is D

Solution and Explanation

Step 1: Identify the top two openers by \emph{highest runs.}
From the table: Highest runs — A: \(141\), B: \(130\), D: \(94\), E: \(85\), C: \(52\).
Thus the top two are A and B. Step 2: Compute their averages ignoring ducks (0's).
A: Total \(= 994\), 0's \(=1\) \(\Rightarrow\) innings counted \(=20-1=19\).
Average(A) \(= \dfrac{994}{19} = 52.3158\ldots\).
B: Total \(= 751\), 0's \(=2\) \(\Rightarrow\) innings counted \(=20-2=18\).
Average(B) \(= \dfrac{751}{18} = 41.7222\ldots\). Step 3: Take the difference.
Difference \(= 52.3158 - 41.7222 = 10.5936\approx 10.6\).
This value is not among the options given. Step 4: Conclude.
\(\boxed{\text{None of these}}\).
Was this answer helpful?
0
0