Length of land = 500 m and Breadth of land = 200 m
Area of land = length x breadth = 500 m x 200 m
= 1,00,000 m2
Cost of tilling 100 sq. m of land = ₹ 8
Cost of tilling 1,00,000 sq. m of land = \(\frac{8}{100}\) x1,00,000 = ₹ 8000
Therefore, the total cost is ₹ 8000
Column I shows different positions in which one pole of a magnet is placed near that of the other. Column II indicates the resulting action between them for each situation. Fill in the blanks.
Column I | Column II |
N-______ | _________ |
N-________ | Attraction |
S-N | |
________-S | Repulsion |
Draw:
1) a leaf
2) a taproot and
3) a flower,
you have studied for Table 4.3