Question:
What is the conductivity of a semiconductor sample having electron concentration of $5 \times 10^{18} \, m^{-3}$, hole concentration of $5 \times 10^{19} \, m^{-3} $ , electron mobility of $2.0 \, m^2 \, V^{-1} \, s^{-1}$ and hole mobility of $0.01 \, m^2 \, V^{-1} \, s^{-1}$ ?
(Take charge of electron as $1.6 \times 10^{-19} C$)
What is the conductivity of a semiconductor sample having electron concentration of $5 \times 10^{18} \, m^{-3}$, hole concentration of $5 \times 10^{19} \, m^{-3} $ , electron mobility of $2.0 \, m^2 \, V^{-1} \, s^{-1}$ and hole mobility of $0.01 \, m^2 \, V^{-1} \, s^{-1}$ ?
(Take charge of electron as $1.6 \times 10^{-19} C$)
Updated On: Feb 2, 2026
- $1.68 (\Omega - m)^{-1}$
- $1.83 (\Omega - m)^{-1}$
- $0.59 (\Omega - m)^{-1}$
- $1.20 (\Omega - m)^{-1}$
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The Correct Option is A
Solution and Explanation
$s = e \left(n_{e}\mu_{e} + n_{n}\mu_{n}\right)$
$= 1.6 ? 10^{-19} \left(5 ? 10^{18} ? 2 + 5 ? 10^{19} ? 0.01\right)$
$= 1.6 ? 10^{-19} \left(10^{19} + 0.05 ? 10^{19}\right)$
$= 1.6 ? 1.05$
$= 1.68$
$= 1.6 ? 10^{-19} \left(5 ? 10^{18} ? 2 + 5 ? 10^{19} ? 0.01\right)$
$= 1.6 ? 10^{-19} \left(10^{19} + 0.05 ? 10^{19}\right)$
$= 1.6 ? 1.05$
$= 1.68$
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Semiconductors
Semiconductors are a crystalline solid materials, whose electrical conductivity lies between a conductor and an insulator. Semiconductors are mainly used in the manufacturing of electronic devices like capacitors, transistors, diodes, Integrated circuits, etc.
Properties of Semiconductor:
- Semiconductor acts like an insulator at Zero Kelvin. On increasing the temperature, it works as a conductor.
- Due to their exceptional electrical properties, semiconductors can be modified by doping to make semiconductor devices suitable for energy conversion, switches, and amplifiers.
- Lesser power losses.
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