Step 1: Understanding the Concept
We need to find the angle between the two hands of a clock at a specific time. We must consider that the hour hand also moves continuously, not just in jumps from one hour to the next.
Step 2: Key Formula or Approach
The formula to find the angle (\(\theta\)) between the hour hand and the minute hand is:
\[ \theta = \left| 30H - \frac{11}{2}M \right| \]
where H is the hour (6 in this case) and M is the minute (30 in this case).
Alternatively, we can calculate the position of each hand individually from the 12 o'clock mark.
Step 3: Detailed Explanation
Method 1: Using the Formula
H = 6, M = 30.
\[ \theta = \left| 30(6) - \frac{11}{2}(30) \right| \]
\[ \theta = \left| 180 - 11 \times 15 \right| \]
\[ \theta = \left| 180 - 165 \right| \]
\[ \theta = 15^\circ \]
Method 2: Calculating Individual Hand Positions
Position of the Minute Hand: The minute hand moves 360° in 60 minutes, which is 6° per minute. At 30 minutes past the hour, its position is:
\[ \text{Angle}_M = 30 \text{ minutes} \times 6^\circ/\text{minute} = 180^\circ \text{ from 12} \]
(This means it is pointing directly at the 6).
Position of the Hour Hand: The hour hand moves 360° in 12 hours, which is 30° per hour or 0.5° per minute. At 6:30, it has moved past the 6.
The total time from 12:00 is 6 hours and 30 minutes = 6.5 hours.
\[ \text{Angle}_H = 6.5 \text{ hours} \times 30^\circ/\text{hour} = 195^\circ \text{ from 12} \]
Angle Between Hands: The difference between their positions.
\[ \theta = |\text{Angle}_H - \text{Angle}_M| = |195^\circ - 180^\circ| = 15^\circ \]
Step 4: Final Answer
The angle between the hour and minute hand at 6:30 is 15 degrees. Therefore, option (C) is the correct answer.