Question:
What is the amount of ROM needed to implement a 4-bit multiplier?
What is the amount of ROM needed to implement a 4-bit multiplier?
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ROM size for a combinational circuit = (Number of input combinations) $\times$ (Output bits).
Updated On: Feb 8, 2026
- 1 Kbits
- 2 Kbits
- 4 Kbits
- 64 bits
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The Correct Option is B
Solution and Explanation
Step 1: Understanding inputs and outputs.
A 4-bit multiplier has two 4-bit inputs. Therefore, total input bits = $4 + 4 = 8$ bits.
Step 2: Calculating number of input combinations.
Number of possible input combinations = $2^8 = 256$.
Step 3: Determining output size.
Multiplying two 4-bit numbers produces an 8-bit result.
Step 4: Calculating ROM size.
Each of the 256 input combinations stores an 8-bit output.
Total ROM size = $256 \times 8 = 2048$ bits = $2$ Kbits.
Step 5: Final conclusion.
Therefore, the amount of ROM needed to implement a 4-bit multiplier is 2 Kbits.
A 4-bit multiplier has two 4-bit inputs. Therefore, total input bits = $4 + 4 = 8$ bits.
Step 2: Calculating number of input combinations.
Number of possible input combinations = $2^8 = 256$.
Step 3: Determining output size.
Multiplying two 4-bit numbers produces an 8-bit result.
Step 4: Calculating ROM size.
Each of the 256 input combinations stores an 8-bit output.
Total ROM size = $256 \times 8 = 2048$ bits = $2$ Kbits.
Step 5: Final conclusion.
Therefore, the amount of ROM needed to implement a 4-bit multiplier is 2 Kbits.
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