Question:

If a concentrated load of 50 kN is applied at point C, then what will be the shear developed at point C? 

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At the point of application of a concentrated load, shear force has a sudden jump equal to the magnitude of the load.
Updated On: Feb 8, 2026
  • 17.5 kN
  • 27.5 kN
  • 37.5 kN
  • 47.5 kN
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The Correct Option is C

Solution and Explanation

Step 1: Identify the support reactions.
The beam is simply supported at points A and B, and a concentrated load of 50 kN acts at point C.
Step 2: Calculate reactions using equilibrium equations.
Taking moments and vertical force equilibrium, the reaction at support A is found to be 37.5 kN, while the reaction at B is 12.5 kN.
Step 3: Determine shear force at point C.
Shear force at point C just to the left of the applied load is equal to the reaction at A.
\[ V_C = 37.5 \text{ kN} \]
Step 4: Conclusion.
Therefore, the shear developed at point C is 37.5 kN.
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