What fraction of one edge centred octahedral void lies in one unit cell of fcc?
\(\frac 13\)
\(\frac 14\)
\(\frac {1}{12}\)
\(\frac 12\)
The Correct Option is B
Solution and Explanation
In a face-centered cubic unit cell, each edge is shared by 4 adjacent unit cells. Therefore, if you consider the edge-centered octahedral void, only \(\frac 14^{th}\) of the void is contained within one unit cell. This is because each unit cell contributes \(\frac 14^{th}\) of the void, and when you sum up the contributions from all adjacent cells, you get the complete void.
So, the correct option is (B): \(\frac 14\)
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Concepts Used:
Solid State
Solids are substances that are featured by a definite shape, volume, and high density. In the solid-state, the composed particles are arranged in several manners. Solid-state, in simple terms, means "no moving parts." Thus solid-state electronic devices are the ones inclusive of solid components that don’t change their position. Solid is a state of matter where the composed particles are arranged close to each other. The composed particles can be either atoms, molecules, or ions.
Types of Solids:
Based on the nature of the order that is present in the arrangement of their constituent particles solids can be divided into two types;
- Amorphous solids behave the same as super cool liquids due to the arrangement of constituent particles in short-range order. They are isotropic and have a broad melting point (range is about greater than 5°C).
- Crystalline solids have a fixed shape and the constituent particles are arranged in a long-range order.