Question

What are X and Y respectively in the following set of reactions?
2-Bromobutane $\xrightarrow{{alc. KOH}}$ C$_4$H$_8$ (major)
C$_4$H$_8$ $\xrightarrow{{KMnO}_4/{H}^+}$ X
C$_4$H$_8$ $\xrightarrow{{Baeyer's reagent}}$ Y

• A. CH₃COOH,      HO-CH(CH₃)-CH₂OH
• B. CH₃CH₂COOH + CO₂,      HO-CH₂-CH₂CH₂OH
• C. CH$_3$COOH, CH$_3$CHO
• D. CH$_3$CH$_2$COOH + CO$_2$, CH$_3$CHO

Hint:

KMnO$_4$/H$^+$ oxidatively cleaves alkenes into carboxylic acids or ketones. Baeyer's reagent gives glycols.

Answer 1

The Correct Option is A

2-Bromobutane on treatment with alc. KOH gives but-2-ene. But-2-ene undergoes oxidative cleavage with KMnO$_4$/H$^+$ to give acetic acid (CH$_3$COOH). Baeyer's reagent reacts with the double bond to give a vicinal diol as the product.