Question

What are X and Y respectively in the following set of reactions? 

 

• A. NaNO\(_2\) | Cu, \(\Delta\); NaF, \(\Delta\)
• B. NaNO\(_2\) | Cu, \(\Delta\); \(\Delta\)
• C. NaNO\(_2\) | \(\Delta\); \(\Delta\)
• D. NaNO\(_2\) | \(\Delta\); NaF, \(\Delta\)

Hint:

In nucleophilic aromatic substitution reactions, fluorine (F) is a good leaving group, and it can be replaced by a variety of nucleophiles such as nitrite (NO\(_2\)).

Answer 1

The Correct Option is B

Step 1: Analyzing the first reaction: In the first reaction, the fluorobenzene (C\(_6\)H\(_5\)F) reacts with N\(_2\)BF\(_4\), and the product obtained is a nitrated product (X). This reaction is a nucleophilic aromatic substitution reaction, where fluorine (a leaving group) is replaced by a nitro group (-NO\(_2\)).
Thus, Y is NaNO\(_2\) in the presence of Cu, and heat (\(\Delta\)).
Step 2: Analyzing the second reaction: In the second reaction, the product obtained from the first reaction (C\(_6\)H\(_5\)X) is treated with sodium nitrite (NaNO\(_2\)) and heated. This results in the formation of a nitro group (-NO\(_2\)) attached to the benzene ring. Thus, X is NaNO\(_2\) in the presence of Cu and heat.
Therefore, the correct answer is option (2).