Rutherford's model of the atom, proposed in 1911, was a significant step forward in atomic theory. It introduced the concept of a dense, positively charged nucleus at the center of the atom, with electrons revolving around it. However, it had several limitations:
Rutherford's model could not explain why the atom is stable. According to classical physics, an electron moving in a circular orbit around the nucleus should continuously lose energy due to acceleration (since it’s constantly changing direction). As the electron loses energy, it would spiral inward and eventually crash into the nucleus, leading to the collapse of the atom. This does not happen in reality, so the model couldn't account for the stability of the atom.
The model also failed to explain the behavior of electrons in motion. According to the laws of electromagnetism, an electron revolving around the nucleus should emit radiation (electromagnetic waves) due to its acceleration. This would lead to a loss of energy and cause the electron to spiral into the nucleus, which again contradicts the observed stability of atoms.
Rutherford’s model could not explain the line spectra of elements. When atoms are heated or excited, they emit light at specific wavelengths, forming a line spectrum. Rutherford’s model could not account for the discrete energy levels seen in these spectra, which suggested that electrons could only occupy certain orbits with fixed energy levels, a concept not present in Rutherford’s model.
Rutherford's model did not provide any insight into how the electrons are distributed in orbits or how they interact with each other. It only described the nucleus and suggested that electrons were revolving around it, without specifying their arrangement in energy levels or shells.
The limitations of Rutherford’s model led to the development of Bohr’s model in 1913. Bohr introduced the idea of quantized energy levels for electrons, which resolved the issues related to the stability of the atom and the atomic spectra.
Express the following linear equations in the form ax + by + c = 0 and indicate the values of a, b and c in each case:
(i) 2x + 3y = 9.35
(ii) x – \(\frac{y}{5}\)– 10 = 0
(iii) –2x + 3y = 6
(iv) x = 3y
(v) 2x = –5y
(vi) 3x + 2 = 0
(vii) y – 2 = 0
Which one of the following options is true, and why? y = 3x + 5 has
(i) a unique solution,
(ii) only two solutions,
(iii) infinitely many solutions