Question

What are \(A\), \(B\), \(C\) in the following reactions?
\[ (i)\; (CH_3CO)_2Ca \xrightarrow{\Delta} A \]
\[ (ii)\; CH_3CO_2H \xrightarrow{HI,\;Red\,P} B \]
\[ (iii)\; 2CH_3CO_2H \xrightarrow{P_4O_{10}} C \]

• A. \(C_2H_6,\; CH_3CO_2O,\; (CH_3CO)_2O\)
• B. \((CH_3CO)_2O,\; C_2H_6,\; CH_3COCH_3\)
• C. \(CH_3COCH_3,\; C_2H_6,\; (CH_3CO)_2O\)
• D. \(CH_3COCH_3,\; (CH_3CO)_2O,\; C_2H_6\)

Hint:

Calcium salts of carboxylic acids on heating give ketones. \(HI/Red\,P\) reduces acids to alkanes. \(P_4O_{10}\) dehydrates acids to anhydrides.

Answer 1

The Correct Option is C

Step 1: Reaction (i).
Calcium acetate on dry distillation gives acetone:
\[ (CH_3CO)_2Ca \xrightarrow{\Delta} CH_3COCH_3 \]
So:
\[ A = CH_3COCH_3 \]
Step 2: Reaction (ii).
Acetic acid reduced with \(HI/Red\,P\) gives ethane:
\[ CH_3COOH \xrightarrow{HI,\;Red\,P} C_2H_6 \]
So:
\[ B = C_2H_6 \]
Step 3: Reaction (iii).
Two moles of acetic acid with \(P_4O_{10}\) gives acetic anhydride:
\[ 2CH_3COOH \xrightarrow{P_4O_{10}} (CH_3CO)_2O \]
So:
\[ C = (CH_3CO)_2O \]
Final Answer:
\[ \boxed{A=CH_3COCH_3,\; B=C_2H_6,\; C=(CH_3CO)_2O} \]