Question:

What amount of water is added in $40\, ml$ of $NaOH (0.1\, N )$ which is neutralized by $50\, ml$ of $HCl (0.2\, N )$ ?

Updated On: Jul 28, 2022
  • 80 ml
  • 60 ml
  • 40 ml
  • 90 ml
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The Correct Option is B

Solution and Explanation

Using Normality equation $N _{1} V _{1}= N _{2} V _{2}$ $0.1 \times V_{1}=0.2 \times 50$ $V_{1}=\frac{0.2 \times 50}{0.1}=100\, ml$ Total volume $= NaOH +$ water $100=40+x$ So amount of water added is $60\, ml$.
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Concepts Used:

Concentration of Solutions

It is the amount of solute present in one liter of solution.

Concentration in Parts Per Million - The parts of a component per million parts (106) of the solution.

Mass Percentage - When the concentration is expressed as the percent of one component in the solution by mass it is called mass percentage (w/w).

Volume Percentage - Sometimes we express the concentration as a percent of one component in the solution by volume, it is then called as volume percentage

Mass by Volume Percentage - It is defined as the mass of a solute dissolved per 100mL of the solution.

Molarity - One of the most commonly used methods for expressing the concentrations is molarity. It is the number of moles of solute dissolved in one litre of a solution.

Molality - Molality represents the concentration regarding moles of solute and the mass of solvent.

Normality - It is the number of gram equivalents of solute present in one liter of the solution and it is denoted by N.

Formality - It is the number of gram formula present in one litre of solution.