Question

Water flows in a horizontal pipe in a streamlined manner at an absolute pressure of \(4 \times 10^5 \, \text{Pa}\) and speed of \(6 \, \text{m/s}\). If it exits the pipe at a pressure of \(10^5 \, \text{Pa}\), the speed of water at the exit point is .......... m/s (Round off to 1 decimal place).
(The density of water is \(1000 \, \text{kg/m}^3\))

Hint:

For horizontal fluid flow, use Bernoulli's equation: \(P + \frac{1}{2}\rho v^2 = \text{constant}\). Always ensure consistent units.

Answer 1

Correct Answer: 25.1 - 25.3

Step 1: Apply Bernoulli's theorem. 
\[ P_1 + \frac{1}{2}\rho v_1^2 = P_2 + \frac{1}{2}\rho v_2^2 \] Substitute given values: \[ 4 \times 10^5 + \frac{1}{2}(1000)(6^2) = 10^5 + \frac{1}{2}(1000)v_2^2 \]

Step 2: Simplify. 
\[ 400000 + 18000 = 100000 + 500v_2^2 \] \[ 500v_2^2 = 318000 \Rightarrow v_2^2 = 636 \Rightarrow v_2 =25.2 \, \text{m/s} \]

Step 3: Conclusion. 
Hence, the exit velocity of water = 25.2 m/s.