Question:
Volume of 0.1 M HCl required to react completely with 1 g equimolar mixture of $Na_2CO_3$ and $NaHCO_3$ is
Volume of 0.1 M HCl required to react completely with 1 g equimolar mixture of $Na_2CO_3$ and $NaHCO_3$ is
Updated On: Jun 23, 2023
- 100 mL
- 200 mL
- 157.9 mL
- 159.7 mL
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The Correct Option is C
Solution and Explanation
$ {NaCO_3 + 2HCl -> 2NaCl + H_2O + CO_2}$
$ { NaHCO_3 + HCl -> NaCl + H_2O + CO_2}$
If the mixture contains 1 mol of each, HCl required is (2 + 1) = 3 mol .
Molar mass of $Na_2CO_3$ = 106 g mol$^{-1}$ .
Molar mass of $NaHCO_3$ = 84 g mol$^{-1}$ .
Thus, 190 g (106 g + 84 g) of mixture require
HCI= 3 mol ,
1 g of mixture require
HCl = $\frac{3}{190} $ mol
$\therefore$ Vol of 0.1 M HCl which contains (3/190) mol
= $\frac{1000 \times 3}{190 \times 0.1} $ = 157.89 mL.
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Concepts Used:
Solutions
A solution is a homogeneous mixture of two or more components in which the particle size is smaller than 1 nm.
For example, salt and sugar is a good illustration of a solution. A solution can be categorized into several components.
Types of Solutions:
The solutions can be classified into three types:
- Solid Solutions - In these solutions, the solvent is in a Solid-state.
- Liquid Solutions- In these solutions, the solvent is in a Liquid state.
- Gaseous Solutions - In these solutions, the solvent is in a Gaseous state.
On the basis of the amount of solute dissolved in a solvent, solutions are divided into the following types:
- Unsaturated Solution- A solution in which more solute can be dissolved without raising the temperature of the solution is known as an unsaturated solution.
- Saturated Solution- A solution in which no solute can be dissolved after reaching a certain amount of temperature is known as an unsaturated saturated solution.
- Supersaturated Solution- A solution that contains more solute than the maximum amount at a certain temperature is known as a supersaturated solution.