\[ (\Delta T_b)_I = \frac{i_X \times w_2}{M_X} \times 1000 \times \frac{w_1}{K_B} \]
\[ (\Delta T_b)_{II} = \frac{i_Y \times w_2}{M_Y} \times 1000 \]
\[ \frac{(\Delta T_b)_I}{(\Delta T_b)_{II}} = \frac{i_X}{w_1} \times K_B \times \frac{M_Y}{i_Y \times M_X} \]
\[ \frac{(\Delta T_b)_I}{(\Delta T_b)_{II}} = \frac{1.2}{1} \times \frac{1}{0.8} = 1.5 \]
\[ (\Delta T_b)_I = 150\% \, \text{of} \, (\Delta T_b)_{II} \]
The elevation of boiling point in Vessel-1 is 150% of the elevation in Vessel-2.