Question:
Value of the determinant \[\begin{vmatrix}1 & w & w^2 \\w & w^2 & 1 \\w^2 & 1 & w\end{vmatrix}\] where \( w \) is the cube root of unity is:
Value of the determinant \[\begin{vmatrix}1 & w & w^2 \\w & w^2 & 1 \\w^2 & 1 & w\end{vmatrix}\] where \( w \) is the cube root of unity is:
Updated On: Jul 12, 2024
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- \( w \)
- \( w^2 \)
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The Correct Option is B
Solution and Explanation
The correct option is (B): 0
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