Question:
Urea reacts with water to form $A$ which will decompose to form $B$. $B$ when passed through $Cu^{2+}(aq)$, deep blue colour solution C is formed.
What is the formula of C from the following
Urea reacts with water to form $A$ which will decompose to form $B$. $B$ when passed through $Cu^{2+}(aq)$, deep blue colour solution C is formed.
What is the formula of C from the following
Updated On: Apr 14, 2025
- $CuSO_4$
- $[Cu(NH_3)_4]^{2+}$
- $Cu(OH)_2$
- $CuCO_3.Cu(OH)_2$
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The Correct Option is B
Solution and Explanation
$NH_{2}CONH_{2}+H_{2}O \to$
$\underset{(A)}{(NH_{4})_{2}CO_{3}} {<=>} \underset{(B)}{2NH_{3}}+H_{2}O+CO_{2}$
$\underset{(B)}{4NH_{3}}+\overset{2+}{Cu(aq)} \to \underset{\text{(deep blue (C)}}{\left[Cu\left(NH_{3}\right)_{4}\right]_{\left(aq\right)}^{2+}}$
$\underset{(A)}{(NH_{4})_{2}CO_{3}} {<=>} \underset{(B)}{2NH_{3}}+H_{2}O+CO_{2}$
$\underset{(B)}{4NH_{3}}+\overset{2+}{Cu(aq)} \to \underset{\text{(deep blue (C)}}{\left[Cu\left(NH_{3}\right)_{4}\right]_{\left(aq\right)}^{2+}}$
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P-Block Elements
- P block elements are those in which the last electron enters any of the three p-orbitals of their respective shells. Since a p-subshell has three degenerate p-orbitals each of which can accommodate two electrons, therefore in all there are six groups of p-block elements.
- P block elements are shiny and usually a good conductor of electricity and heat as they have a tendency to lose an electron. You will find some amazing properties of elements in a P-block element like gallium. It’s a metal that can melt in the palm of your hand. Silicon is also one of the most important metalloids of the p-block group as it is an important component of glass.
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