In electrostatics, it is a well-established fact that:
- Excess charge always resides on the surface of a conductor. This is because like charges repel each other, so they tend to spread out over the surface of the conductor.
- The electric field inside a conductor in electrostatic equilibrium is zero because the charges move to cancel out any internal fields.
- The electric field at the surface of a conductor is perpendicular to the surface (not tangential).
Thus, the correct statement is that any excess charge resides on the surface of the conductor.
Consider two concentric conducting spherical shells as shown in the figure. The inner shell has a radius \(a\) and carries a charge \(+Q\). The outer shell has a radius \(b\) and carries a charge \(-Q\). The empty space between them is half-filled by a hemispherical shell of a dielectric having permittivity \(\epsilon_1\). The remaining space between the shells is filled with air having the permittivity \(\epsilon_0\).

The electric field at a radial distance \(r\) from the center and between the shells \((a < r < b)\) is
The circuit shown in the figure contains two ideal diodes \( D_1 \) and \( D_2 \). If a cell of emf 3V and negligible internal resistance is connected as shown, then the current through \( 70 \, \Omega \) resistance (in amperes) is: 