Let's evaluate each statement in relation to electrostatic conditions of a charged conductor.
Option (A): The electric field on the surface of a charged conductor is \( \frac{\sigma}{\epsilon_0} \), where \( \sigma \) is the surface charge density
This statement is correct, as the electric field at the surface of a conductor under electrostatic conditions is given by the formula:
\[ E = \frac{\sigma}{\epsilon_0} \]
So, this statement is true.
Option (B): The electric potential inside a charged conductor is always zero
This is incorrect. The electric potential inside a charged conductor is constant, but it is not always zero. It depends on the configuration of the conductor.
This statement is correct. Under electrostatic conditions, any excess charge on a conductor resides on its surface. This is due to the repulsion of like charges, causing them to spread out evenly across the surface.
This is incorrect. The net electric field inside the conductor is zero, and the field at the surface is normal (perpendicular) to the surface of the conductor.
The correct answer is (C) Any excess charge resides on the surface of the conductor.
Match List - I with List - II:
List - I:
(A) Electric field inside (distance \( r > 0 \) from center) of a uniformly charged spherical shell with surface charge density \( \sigma \), and radius \( R \).
(B) Electric field at distance \( r > 0 \) from a uniformly charged infinite plane sheet with surface charge density \( \sigma \).
(C) Electric field outside (distance \( r > 0 \) from center) of a uniformly charged spherical shell with surface charge density \( \sigma \), and radius \( R \).
(D) Electric field between two oppositely charged infinite plane parallel sheets with uniform surface charge density \( \sigma \).
List - II:
(I) \( \frac{\sigma}{\epsilon_0} \)
(II) \( \frac{\sigma}{2\epsilon_0} \)
(III) 0
(IV) \( \frac{\sigma}{\epsilon_0 r^2} \) Choose the correct answer from the options given below: