Question:
Ultimate product is obtained on heating $B_{2} H_{6}$ with $N H_{3}$ is
Ultimate product is obtained on heating $B_{2} H_{6}$ with $N H_{3}$ is
Updated On: Jun 14, 2022
- $B_{3} N_{3} H_{6}$
- $(B-N)_{3}$
- $N _{2} H _{4}$
- $B H_{4 .}^{-}$
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The Correct Option is A
Solution and Explanation
$3 B_{2} H_{6}+6 N H_{3} \xrightarrow{200^{\circ} C } \underset{\text { Borazine or borazole }}{2 B_{3} N_{3} H_{6}+12 H_{2}}$
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Concepts Used:
P-Block Elements
- P block elements are those in which the last electron enters any of the three p-orbitals of their respective shells. Since a p-subshell has three degenerate p-orbitals each of which can accommodate two electrons, therefore in all there are six groups of p-block elements.
- P block elements are shiny and usually a good conductor of electricity and heat as they have a tendency to lose an electron. You will find some amazing properties of elements in a P-block element like gallium. It’s a metal that can melt in the palm of your hand. Silicon is also one of the most important metalloids of the p-block group as it is an important component of glass.
P block elements consist of:
- Group 13 Elements: Boron family
- Group 14 Elements: Carbon family
- Group 15 Elements: Nitrogen family
- Group 16 Elements: Oxygen family
- Group 17 Elements: Fluorine family
- Group 18 Elements: Neon family