Two rods \(A\) and \(B\) of different materials are welded together as shown in figure. Their thermal conductivities are \(K_1\) and \(K_2\). The thermal conductivity of the composite rod will be :
$R _{1}=\frac{ d }{ k _{1} A }$ $R _{2}= d K _{2} A$ $\operatorname{Req}=\frac{ R _{1} R _{2}}{ R _{1}+ R _{2}}$ $\frac{ d }{ keq (2 A )}=\frac{\left(\frac{ d }{ k _{1} A }\right)\left(\frac{ d }{ k _{2} A }\right)}{ A }\left(\frac{1}{ k _{1}}+\frac{1}{ k _{2}}\right)$ $\frac{1}{2 keq }=\frac{\frac{1}{ k _{1} k _{2}}}{\frac{ k _{1}+ k _{2}}{ k _{1} k _{2}}}=\frac{1}{ k _{1}+ k _{2}}$ $keq =\frac{ k _{1}+ k _{2}}{2}$