Step 1: Lens formula.
The power of a lens is given by:
\[
P = \frac{1}{f}
\]
where \( f \) is the focal length. The total power \( P_{\text{total}} \) of two lenses in contact is the sum of their individual powers:
\[
P_{\text{total}} = P_1 + P_2
\]
Step 2: Power of the lenses.
Given the focal length of the combination \( f_{\text{total}} = 80 \, \text{cm} \), the power of the combination is:
\[
P_{\text{total}} = \frac{1}{f_{\text{total}}} = \frac{1}{0.80} = 1.25 \, \text{D}
\]
The power of the first lens is:
\[
P_1 = \frac{1}{f_1} = \frac{1}{20} = 5 \, \text{D}
\]
Thus, the power of the second lens is:
\[
P_2 = P_{\text{total}} - P_1 = 1.25 - 5 = 4.00 \, \text{D}
\]
Final Answer:
\[
\boxed{4.00 \, \text{D}}
\]