Two taps fill the tank at rates of \(\frac{V}{20}\) and \(\frac{V}{30}\) liters per minute, and an outlet removes 50 liters per minute when the tank is half full.
In the first 12 minutes, the taps fill half the tank:
\(\left( \frac{V}{12} \right) \times 12 = \frac{V}{2}\).
In the next 12 minutes (with the outlet open), the filling rate becomes \(\frac{V}{12} - 50\) liters per minute.
Setting this equal to half the tank:
\(\Rightarrow\;\)\(\frac{V}{12} \times 12 - 600 = \frac{V}{2}\)
\(\Rightarrow\;\)\(V = 1440\) liters.
Thus, the tank's volume is 1440 liters.