Question:

Two tailors A and B earn 150 and 200 per day respectively. A can stitch 6 shirts and 4 pants per day, while B can stitch 10 shirts and 4 pants per day. If the tailors A and B work for x and y days respectively. To maximize the earning for producing at least 60 shirts and 32 pants, the LPP is:

Updated On: May 18, 2024
  • Maximize Z = 150x + 200y, subject to 6x + 10y \(\geq\) 60, 4x + 4y \(\geq\) 32, x, y \(\geq\) 0
  • Maximize Z = 150x + 200y, subject to 6x + 10y \(\leq\) 60, 4x + 4y \(\leq\) 32, x, y \(\geq\) 0
  • Maximize Z = 150x + 200y, subject to 6x + 4y \(\geq\) 60, 10x + 4y \(\geq\) 32, x, y \(\geq\) 0
  • Maximize Z = 150x + 200y, subject to 6x + 10y \(\geq\) 60, 4x + 4y \(\leq\) 32, x, y \(\geq\) 0
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The Correct Option is A

Solution and Explanation

The correct option is (A): Maximize Z = 150x + 200y, subject to 6x + 10y \(\geq\) 60, 4x + 4y \(\geq\) 32, x, y \(\geq\) 0
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