The line segment \(AB\) has the points \(A(0, 8)\) and \(B(4, 0)\). The objective function \(Z = ax + by\) will have a maximum value on \(AB\) if \(\frac{a}{b} = -\frac{\text{change in } y}{\text{change in } x}\).
Between points \(A\) and \(B\):
Slope of \(AB\) is given by:
\[\text{Slope of } AB = \frac{0 - 8}{4 - 0} = -2\]Thus, the ratio \(\frac{a}{b} = 2\) implies \(a = 2b\).
The line segment \(AB\) has the points \(A(0, 8)\) and \(B(4, 0)\). The objective function \(Z = ax + by\) will have a maximum value on \(AB\) if \(\frac{a}{b} = -\frac{\text{change in } y}{\text{change in } x}\).
Between points \(A\) and \(B\):
Step 1: Calculate the slope of the line segment \(AB\).
The formula for the slope of a line is given by:
\[ \text{Slope of } AB = \frac{y_2 - y_1}{x_2 - x_1} \] where \((x_1, y_1)\) and \((x_2, y_2)\) are the coordinates of the points \(A\) and \(B\). For the points \(A(0, 8)\) and \(B(4, 0)\), we have: \[ \text{Slope of } AB = \frac{0 - 8}{4 - 0} = \frac{-8}{4} = -2 \]Step 2: Relating the slope to the objective function.
The objective function \(Z = ax + by\) has a maximum value when the ratio \(\frac{a}{b}\) matches the negative of the slope of the line segment \(AB\), i.e., \[ \frac{a}{b} = -\text{Slope of } AB \] Substituting the value of the slope: \[ \frac{a}{b} = -(-2) = 2 \]Step 3: Expressing the relationship between \(a\) and \(b\).
From the equation \(\frac{a}{b} = 2\), we can express \(a\) in terms of \(b\): \[ a = 2b \]Conclusion: The objective function will have a maximum value on the line segment \(AB\) if \(a = 2b\).
Assertion (A): The corner points of the bounded feasible region of a L.P.P. are shown below. The maximum value of \( Z = x + 2y \) occurs at infinite points.
Reason (R): The optimal solution of a LPP having bounded feasible region must occur at corner points.
The maximum value of \( Z = 4x + y \) for a L.P.P. whose feasible region is given below is: