Question:

The corner points of the feasible region determined by $x + y \leq 8$, $2x + y \geq 8$, $x \geq 0$, $y \geq 0$ are $A(0, 8)$, $B(4, 0)$, and $C(8, 0)$. If the objective function $Z = ax + by$ has its maximum value on the line segment $AB$, then the relation between $a$ and $b$ is:

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When dealing with linear optimization problems, the slope of the constraint line often provides a critical relationship between the coefficients of the objective function. Make sure to relate the slope of the constraint line to the ratio of coefficients for finding optimal values.
Updated On: Mar 30, 2025
  • $8a + 4 = b$
  • $a = 2b$
  • $b = 2a$
  • $8b + 4 = a$
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The Correct Option is B

Approach Solution - 1

The line segment \(AB\) has the points \(A(0, 8)\) and \(B(4, 0)\). The objective function \(Z = ax + by\) will have a maximum value on \(AB\) if \(\frac{a}{b} = -\frac{\text{change in } y}{\text{change in } x}\).

Between points \(A\) and \(B\):

Slope of \(AB\) is given by:

\[\text{Slope of } AB = \frac{0 - 8}{4 - 0} = -2\]

Thus, the ratio \(\frac{a}{b} = 2\) implies \(a = 2b\).

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Approach Solution -2

The line segment \(AB\) has the points \(A(0, 8)\) and \(B(4, 0)\). The objective function \(Z = ax + by\) will have a maximum value on \(AB\) if \(\frac{a}{b} = -\frac{\text{change in } y}{\text{change in } x}\).

Between points \(A\) and \(B\):

Step 1: Calculate the slope of the line segment \(AB\).

The formula for the slope of a line is given by:

\[ \text{Slope of } AB = \frac{y_2 - y_1}{x_2 - x_1} \] where \((x_1, y_1)\) and \((x_2, y_2)\) are the coordinates of the points \(A\) and \(B\). For the points \(A(0, 8)\) and \(B(4, 0)\), we have: \[ \text{Slope of } AB = \frac{0 - 8}{4 - 0} = \frac{-8}{4} = -2 \]

Step 2: Relating the slope to the objective function.

The objective function \(Z = ax + by\) has a maximum value when the ratio \(\frac{a}{b}\) matches the negative of the slope of the line segment \(AB\), i.e., \[ \frac{a}{b} = -\text{Slope of } AB \] Substituting the value of the slope: \[ \frac{a}{b} = -(-2) = 2 \]

Step 3: Expressing the relationship between \(a\) and \(b\).

From the equation \(\frac{a}{b} = 2\), we can express \(a\) in terms of \(b\): \[ a = 2b \]

Conclusion: The objective function will have a maximum value on the line segment \(AB\) if \(a = 2b\).


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