Question:

Two sources of equal emf are connected to a resistance $R$. The internal resistance of these sources are $r_1$ and $r_2 (r_1 > r_2 )$. If the potential difference across the source having internal resistance $r_2$ is zero, then

Updated On: Apr 22, 2024
  • $R = \frac{r_1 r_2}{r_2 - r_1}$
  • $R = r_2 \left( \frac{r_1 + r_2}{r_2 - r_1} \right)$
  • $R = \left( \frac{r_1 r_2}{r_2 - r_1} \right)$
  • $R = r_2 - r_1$
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The Correct Option is D

Solution and Explanation

Let E be the emf of each source. When they are connected in series, then the current in the circuit is given by
$I = \frac{E_{tot}}{R_{tot}} = \frac{E +E}{r_{1 } + r_{2} + R} $
$= \frac{2E}{r_{1} + r_{2} + R} $
So, potential drop across the cell of internal resistance
$ r_{2} , \left(\frac{2E}{r_{1} + r_{2} + R}\right) r_{2}$
Hence, $ E - \frac{2E}{ \left(r_{1} + r_{2} + R\right)} r_{2} = 0 $
$ r_{1} + r_{2} + R = 2r_{2} $
So $ R = r_{2} - r_{1} $
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The magnetic field is a field created by moving electric charges. It is a force field that exerts a force on materials such as iron when they are placed in its vicinity. Magnetic fields do not require a medium to propagate; they can even propagate in a vacuum. Magnetic field also referred to as a vector field, describes the magnetic influence on moving electric charges, magnetic materials, and electric currents.

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