
Assuming the standard textbook circuit:
A 10 V battery is connected in series with two silicon diodes (each with forward drop 0.7 V) and two resistors of 10 Ω each.
Total diode drop:
\[ V_D = 0.7 + 0.7 = 1.4\ \text{V} \] Total series resistance:
\[ R = 10 + 10 = 20\ \Omega \] Current through the battery:
\[ I = \frac{V_{\text{battery}} - V_D}{R} \] \[ I = \frac{10 - 1.4}{20} = \frac{8.6}{20} = 0.43\ \text{A} \] Final Answer:
\[ \boxed{0.43\ \text{A}} \]
(i) Study the diagram and name the parts marked as A, B, C, and D.
(ii) Write the function of A and C.
