Question

Two reactors of volumes 5 L and 10 L contain an ideal gas at 9 atm and 6 atm. When the valve is opened, the final equilibrium pressure (atm) of the system is \(\underline{\hspace{1cm}}\).

Hint:

For mixing gases at constant temperature, use weighted average of pressures.

Answer 1

Correct Answer: 7

Using ideal gas law at constant temperature:
\[ P_{\text{final}} = \frac{P_1 V_1 + P_2 V_2}{V_1 + V_2} \]
Substituting:
\[ P_{\text{final}} = \frac{9 \times 5 + 6 \times 10}{5 + 10} = \frac{45 + 60}{15} = \frac{105}{15} = 7 \text{ atm} \]