Two objects of mass 10 kg and 20 kg respectively are connected to the two ends of a rigid rod of length 10 m with negligible mass. The distance of the center of mass of the system from the 10 kg mass is:
- \(\frac{10}{3} m\)
- \(\frac{20}{3} m\)
- \(10 m\)
- \(5 m\)
The Correct Option is B
Solution and Explanation
The correct option is (B) : \(\frac{20}{3} m\).
\(x = [\frac{m_{2r}}{(m_1+m_2)}]\)
\(= [\frac{20(20)}{(20+10)}]\)
\(= \frac{200}{30}\)
\(= \frac{20}{3}\)
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Concepts Used:
Momentum
It can be defined as "mass in motion." All objects have mass; so if an object is moving, then it is called as momentum.
the momentum of an object is the product of mass of the object and the velocity of the object.
Momentum = mass • velocity
The above equation can be rewritten as
p = m • v
where m is the mass and v is the velocity.
Momentum is a vector quantity and the direction of the of the vector is the same as the direction that an object.