Question:

Two objects of mass 10 kg and 20 kg respectively are connected to the two ends of a rigid rod of length 10 m with negligible mass. The distance of the center of mass of the system from the 10 kg mass is:
Two objects of mass 10 kg and 20 kg

Updated On: Sep 13, 2024
  • \(\frac{10}{3} m\)
  • \(\frac{20}{3} m\)
  • \(10 m\)
  • \(5 m\)
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The Correct Option is B

Solution and Explanation

The correct option is (B) : \(\frac{20}{3} m\).

Two objects of mass 10 kg and 20 kg

\(x = [\frac{m_{2r}}{(m_1+m_2)}]\)
\(= [\frac{20(20)}{(20+10)}]\)
\(= \frac{200}{30}\)
\(= \frac{20}{3}\)

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Questions Asked in NEET exam

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Concepts Used:

Momentum

It can be defined as "mass in motion." All objects have mass; so if an object is moving, then it is called as momentum.

the momentum of an object is the product of mass of the object and the velocity of the object.

Momentum = mass • velocity

The above equation can be rewritten as

p = m • v

where m is the mass and v is the velocity. 

Momentum is a vector quantity and  the direction of the of the vector is the same as the direction that an object.