Question:

Two numbers are in the ratio of 15:11. If their H.C.F. is 12, find the Numbers.

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To find actual numbers from a ratio given their HCF, multiply each part of the ratio by the HCF.
Updated On: Mar 25, 2025
  • 180,132
  • 186,165
  • 184,139
  • 133,169
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The Correct Option is A

Solution and Explanation

Step 1: Let the numbers be \( 15x \) and \( 11x \), where \( x \) is the common multiplier.
Step 2: Since the HCF of the numbers is 12, we have:
\[ \text{HCF}(15x, 11x) = 12 \] Step 3: The HCF of 15 and 11 is 1, so:
\[ x = 12 \] Step 4: The numbers are:
\[ 15x = 15 \times 12 = 180 \] \[ 11x = 11 \times 12 = 132 \] Thus, the numbers are 180 and 132.
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