Question:
Two infinitely long wires carry linear charge densities $+ \lambda$ and $- \lambda$ respectively as shown. The potential difference between points A (at a distance a from the first wire) and B (at a distance b from the second wire) is
Two infinitely long wires carry linear charge densities $+ \lambda$ and $- \lambda$ respectively as shown. The potential difference between points A (at a distance a from the first wire) and B (at a distance b from the second wire) is
Updated On: Jun 20, 2022
- $\frac{\lambda}{2 \pi\varepsilon_{0}} ln \left(\frac{\left(d-a\right)\left(d-b\right)}{ab}\right)$
- $\frac{\lambda}{2 \pi\varepsilon_{0}} ln \left(\frac{d^2}{ab}\right)$
- $\frac{\lambda}{4 \pi\varepsilon_{0}} ln \left(\frac{\left(d-a\right)\left(d-b\right)}{ab}\right)$
- $\frac{\lambda}{2 \pi\varepsilon_{0}} \left(\frac{\left(d-a\right)\left(d-b\right)}{ab}\right)$
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The Correct Option is D
Solution and Explanation
Electric force at a point due to a linear charge distribution is given by
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Concepts Used:
Electrostatic Potential
The electrostatic potential is also known as the electric field potential, electric potential, or potential drop is defined as “The amount of work that is done in order to move a unit charge from a reference point to a specific point inside the field without producing an acceleration.”
SI Unit of Electrostatic Potential:
SI unit of electrostatic potential - volt
Other units - statvolt
Symbol of electrostatic potential - V or φ
Dimensional formula - ML2T3I-1
Electric Potential Formula:
The electric potential energy of the system is given by the following formula:
U = 1/(4πεº) × [q1q2/d]
Where q1 and q2 are the two charges that are separated by the distance d.