Question:

Two identical circles intersect so that their centres, and the points at which they intersect, form a square of side 2 cm. What is the area of the portion that is common to both the circles?

IBSAT

Updated On: Jul 24, 2024

$2(\pi– 2) cm^2$
$2(\pi – 1) cm^2$
$2\pi cm^2$
$(\pi – 2) cm^2$
$(\pi – 1) cm^2$

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The Correct Option is A

Solution and Explanation

The correct option is (A):

2(\pi– 2) cm^2

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