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two identical circles intersect so that their cent
Question:
Two identical circles intersect so that their centres, and the points at which they intersect, form a square of side 2 cm. What is the area of the portion that is common to both the circles?
IBSAT
Updated On:
Jul 24, 2024
$2(\pi– 2) cm^2 $
$2(\pi – 1) cm^2 $
$2\pi cm^2 $
$(\pi – 2) cm^2 $
$(\pi – 1) cm^2 $
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The Correct Option is
A
Solution and Explanation
The correct option is (A): $2(\pi– 2) cm^2 $
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