Question

Two glass bulbs A and B are connected by a very small tube having a stop-cock. Bulb A has a volume of 100 cm\(^3\) and contained the gas while bulb B was empty. On opening the stop-cock, the pressure fell down to 40%. The volume of the bulb B must be:

• A. 250 cm\(^3\)
• B. 150 cm\(^3\)
• C. 500 cm\(^3\)
• D. 400 cm\(^3\)

Hint:

Boyle's Law relates the pressure and volume of a gas at constant temperature: \( P_1 V_1 = P_2 V_2 \).

Answer 1

The Correct Option is C

Step 1: Understand the problem.
When the stop-cock is opened, the pressure drops to 40%, indicating an expansion of the gas. Using Boyle’s Law, we can relate the change in volume with the pressure.
Step 2: Calculation.
By applying Boyle’s Law \( P_1 V_1 = P_2 V_2 \), we can calculate the volume of bulb B, which comes out to be 500 cm\(^3\).
Final Answer: \[ \boxed{500 \, \text{cm}^3} \]